0.3x^2-4.2x+1.6=0

Solution for 0.3x^2-4.2x+1.6=0 equation:

0.3x^2-4.2x+1.6=0

a = 0.3; b = -4.2; c = +1.6;
Δ = b2-4ac
Δ = -4.22-4·0.3·1.6
Δ = 15.72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.2)-\sqrt{15.72}}{2*0.3}=\frac{4.2-\sqrt{15.72}}{0.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.2)+\sqrt{15.72}}{2*0.3}=\frac{4.2+\sqrt{15.72}}{0.6}
$